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How do you solve the following system?: # 6x+6y=-1 , 2x -5y=7 #

Answer 1

#x=37/22,y=-22/21#

Multiplying the second equation by #-3# and adding to the first we get #y=-22/21# plugging this in the second equation we get #x=1/2(7-110/21)# #x=37/42#

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Answer 2

Abigail Allen

To solve the system of equations:

6x + 6y = -1
2x - 5y = 7

Multiply the second equation by 3 to eliminate x by adding it to the first equation:

6x + 6y = -1
6x - 15y = 21

Add the equations together to eliminate x:

12y = 20

Solve for y:

y = 20/12 = 5/3

Substitute y = 5/3 into one of the original equations to solve for x:

6x + 6(5/3) = -1

6x + 10 = -1

6x = -11

x = -11/6

The solution to the system is x = -11/6 and y = 5/3.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.