How do you solve the following system: #4x5y23=0 , 2x=6y+18 #?
This gives:
This gives:
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To solve the system of equations:

Rearrange the second equation to express x in terms of y: 2x = 6y + 18 Divide both sides by 2: x = 3y  9

Substitute the expression for x from the second equation into the first equation: 4(3y  9)  5y  23 = 0

Simplify and solve for y: 12y  36  5y  23 = 0 17y  59 = 0 17y = 59 y = 59/17

Substitute the value of y back into either of the original equations to solve for x: x = 3(59/17)  9 x ≈ 21/17
So, the solution to the system of equations is approximately (21/17, 59/17).
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When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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