# How do you solve the following system: #3x + 2y = 1, 2x - 3y = 10 #?

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To solve the system of equations (3x + 2y = 1) and (2x - 3y = 10), you can use either the substitution method or the elimination method. Let's use the elimination method.

First, multiply both equations by suitable constants to make the coefficients of one of the variables the same or additive inverses. In this case, we can multiply the first equation by 3 and the second equation by 2 to make the coefficients of (x) the same:

(9x + 6y = 3) (4x - 6y = 20)

Now, add the equations together:

(9x + 6y + 4x - 6y = 3 + 20)

This simplifies to:

(13x = 23)

Now, solve for (x):

(x = \frac{23}{13})

Next, substitute the value of (x) into one of the original equations to solve for (y). Let's use the first equation:

(3(\frac{23}{13}) + 2y = 1)

Solve for (y):

(y = -\frac{4}{13})

So, the solution to the system of equations is (x = \frac{23}{13}) and (y = -\frac{4}{13}).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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