# How do you solve the following linear system: # y=2x-1, x-y=5 #?

The solution for the system of equations is

using substitution to solve.

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To solve the linear system ( y = 2x - 1 ) and ( x - y = 5 ):

- Substitute the expression for ( y ) from the first equation into the second equation.
- This gives ( x - (2x - 1) = 5 ).
- Simplify by distributing the negative sign: ( x - 2x + 1 = 5 ).
- Combine like terms: ( -x + 1 = 5 ).
- Subtract 1 from both sides: ( -x = 4 ).
- Divide both sides by -1: ( x = -4 ).
- Substitute ( x = -4 ) into the first equation to find ( y ): ( y = 2(-4) - 1 ).
- Simplify: ( y = -8 - 1 ).
- Compute: ( y = -9 ).
- So, the solution to the system is ( x = -4 ) and ( y = -9 ).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

- Is (-5, -9) a solution to this system of equations #18x-12y=18, 11x-6y=-1#?
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- How do you solve the following system: #-5x + 3y= 6, 8x-3y=3 #?
- How do you solve the following system?: # x + 2y = -2 , y=2x+9 #
- How to solve for y in #5x-y=33# and #7x+y=51#?

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