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How do you solve the equation #x^2 - 4x = 4#?

Answer 1

Ethan Adkins

#x^2-4x=4#

#=>x^2-4x+4=8#

#a = x# #b = 2#

#a^2-2ab+b^2 = (a-b)^2#

#(x-2)^2=8#

#x-2 = sqrt(8)# or #-sqrt(8)#

#x_1 = sqrt(8)+2#

#x_2= -sqrt(8)+2#

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Answer 2

Nathan Axel

To solve the equation (x^2 - 4x = 4), follow these steps:

Move all terms to one side to set the equation to zero: (x^2 - 4x - 4 = 0).
Use the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}), where (a = 1), (b = -4), and (c = -4).
Substitute the values of (a), (b), and (c) into the quadratic formula.
Solve for (x) by computing the values under the square root and performing the arithmetic.
The solutions will be the values of (x).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.