How do you solve the equation by graphing #x^2 + 5x + 8 = 0#?

D = b^2 - 4ac = 25 - 32 = -7 <0.Graph the equation y = x^2 + 5x + 8 graph{x^2 + 5x + 8 [-10, 10, -5, 5]}.There are no real roots (no x-intercepts). The graph is entirely above the x-axis.

To solve the equation by graphing (x^2 + 5x + 8 = 0), you can graph the quadratic function (y = x^2 + 5x + 8) and find the x-coordinates of the points where the graph intersects the x-axis. These x-coordinates are the solutions to the equation. If the graph doesn't intersect the x-axis, then the equation has no real solutions.

Alternatively, you can use the quadratic formula, which states that for any quadratic equation in the form (ax^2 + bx + c = 0), the solutions are given by:

[x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}]

For (x^2 + 5x + 8 = 0), (a = 1), (b = 5), and (c = 8). Plugging these values into the quadratic formula will give you the solutions for (x).