How do you solve the equation and identify any extraneous solutions for #(3x^3)/4=192#?
There is only one viable fix for this:
The other two complex roots, in case you were wondering, are:
is referred to as the unity's primitive cube root.
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To solve the equation (\frac{3x^3}{4} = 192), follow these steps:

Multiply both sides by 4 to clear the fraction: (3x^3 = 192 \times 4)
 This simplifies to: (3x^3 = 768)

Divide both sides by 3 to isolate (x^3): (x^3 = \frac{768}{3})
 Simplifying the right side gives: (x^3 = 256)

Take the cube root of both sides to solve for (x): (x = \sqrt[3]{256})
 The cube root of 256 is 4, so (x = 4)
To identify any extraneous solutions, substitute (x = 4) back into the original equation:
(\frac{3(4)^3}{4} = 192)
Solving this equation: (\frac{3 \times 64}{4} = 192) (3 \times 16 = 192) (48 = 192)
Since (48 \neq 192), there are no extraneous solutions. Therefore, the solution to the equation is (x = 4).
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When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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