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How do you solve the equation #4(x+5)^2=-64#?

Answer 1

Genesis Allen

#x=-5+-4i#

#"Isolate " (x+5)^2" by dividing both sides by 4"#

#rArr(x+5)^2=-16#

#(x+5)^2>=0" thus no true roots exist"#

#x+5=+-sqrt(-16)#

(x+5) #color(white)=+-4i#

#rArrx = 5 + 4i#

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Answer 2

Savannah Anderson

To solve the equation 4(x + 5)^2 = -64, first, divide both sides by 4 to isolate the squared term. Then, take the square root of both sides to solve for x. This leads to (x + 5)^2 = -16. Since the square of any real number is non-negative, there are no real solutions for x in this equation.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.