How do you solve the equation #2x – 7 – (x – 5) = 0#?

Answer 1

#color(blue)(x=2#

#2x -7- (x-5) =0#
#2x -7-x+5 =0#
#2x -x-7+5 =0#
#x-2 =0#
#color(blue)(x=2#
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Answer 2

To solve the equation 2x – 7 – (x – 5) = 0:

  1. Distribute the negative sign inside the parentheses: 2x – 7 – x + 5 = 0.
  2. Combine like terms: 2x – x – 7 + 5 = 0, which simplifies to x – 2 = 0.
  3. Add 2 to both sides: x – 2 + 2 = 0 + 2.
  4. The equation becomes x = 2.
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Answer 3

To solve the equation (2x - 7 - (x - 5) = 0), follow these steps:

  1. Remove the parentheses using the distributive property:

[2x - 7 - x + 5 = 0]

  1. Combine like terms:

[2x - x - 7 + 5 = 0] [x - 2 = 0]

  1. Add 2 to both sides of the equation:

[x - 2 + 2 = 0 + 2] [x = 2]

So, the solution to the equation (2x - 7 - (x - 5) = 0) is (x = 2).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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