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How do you solve the compound inequality #h-10< -21# or #h+3<2#?

Answer 1

Ethan Adkins

Solution: # h <-11 or (-oo , -11)#

#h-10<-21 or h < -21+10 or h < -11# or

#h+3<2 or h < 2-3 or h < -1#

The intersection of the two solutions is # h <-11#

Solution: # h <-11 or (-oo , -11)# [Ans]

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Answer 2

Kennedy Adams

#(-oo,-11)#

#"solve both inequalities"#

#h-10<-21larr" add 10 to both sides"#

#rArrh<-11#

#h+3<2larr" subtract 3 from both sides"#

#rArrh<-1#

#-11 < h < -1" only satisfies "h+3<2#

#"whereas "x < -11" satisfies both inequalities"#

#rArr(-oo,-11)" is the solution"#

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Answer 3

Eva Abramson

To solve the compound inequality (h - 10 < -21) or (h + 3 < 2), you solve each inequality separately.

For (h - 10 < -21): Add 10 to both sides: (h < -21 + 10) (h < -11)

For (h + 3 < 2): Subtract 3 from both sides: (h < 2 - 3) (h < -1)

So, the solution to the compound inequality is (h < -11) or (h < -1).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

How do you solve the compound inequality #h-10&lt; -21# or #h+3&lt;2#?

How do you solve the compound inequality #h-10< -21# or #h+3<2#?