How do you solve #T=(3R)/(M-N) # for R?

Answer 1

Remember #a/b=c/d->ad=bc# (cross-product)

#T/1=(3R)/(M-N)->T*(M-N)=1*3R->#
#3R=T(M-N)->R=1/3 T(M-N)=(T(M-N))/3#
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Answer 2

#R=(TM-TN)/3#

First of you need to multiply both sides by #M-N#; #T(M-N)=(3R)/(M-N)(M-N)=TM-TN=3R# Then you need to divide both sides by three; #(TM-TN)/3=(3R)/3=(TM-TN)/3=R# Hope that helps :)
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Answer 3

To solve for ( R ) in the equation ( T = \frac{3R}{M - N} ), first multiply both sides by ( M - N ) to isolate ( R ). Then divide both sides by ( 3 ) to solve for ( R ). The equation becomes ( R = \frac{T(M - N)}{3} ).

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Answer 4

To solve ( T = \frac{3R}{M-N} ) for ( R ), you would:

[ R = \frac{T(M-N)}{3} ]

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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