# How do you solve #(t+3)/5=(2t+3)/9#?

We're left with

We can distribute the constants outside to get

Hope this helps!

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To solve the equation (t+3)/5=(2t+3)/9, you can cross-multiply and then solve for t. First, multiply both sides of the equation by 5 and 9 to eliminate the denominators. This gives you 9(t+3) = 5(2t+3). Expanding the equation, you get 9t + 27 = 10t + 15. Next, subtract 9t from both sides to isolate the variable, resulting in 27 = t + 15. Finally, subtract 15 from both sides to solve for t, giving you t = 12.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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