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How do you solve #T+28+T=4(T-13)#?

Answer 1

Eva Abramson

#T = 40#

#T + 28 + T = 4 (T-13)#

#T + 28 + T = 4T - 52#

#T + T = 4T - 52 - 28#

#T + T - 4T = - 52 - 28#

#- 2T = - 52 - 28#

#- 2T = -80#

#T = -80 ÷ -2#

#color(blue)(T = 40#

Now we can put #40# in for #T# to prove our answer.

#40 + 28 + 40 = 4 (40 -13)#

#68 + 40 = 4 (40 -13)#

#68 + 40 = 4 xx 27#

#68 + 40 = 108#

#108 = 108#

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Answer 2

Isaiah Anthony

To solve the equation T + 28 + T = 4(T - 13), first simplify both sides of the equation. Then, combine like terms and solve for T.

T + 28 + T = 4(T - 13) 2T + 28 = 4T - 52 28 = 2T - 52 80 = 2T T = 40

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Answer 3

Abigail Allen

To solve ( T + 28 + T = 4(T - 13) ), first distribute (4) on the right side of the equation:

( T + 28 + T = 4T - 52 )

Combine like terms on the left side:

( 2T + 28 = 4T - 52 )

Subtract (2T) from both sides:

( 28 = 2T - 52 )

Add (52) to both sides:

( 80 = 2T )

Divide both sides by (2):

( T = 40 )

So, the solution to the equation is ( T = 40 ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.