How do you solve #sqrt (x-7) = sqrt (x) - 1#?

Question

Hazel Anglin · Accepted Answer

We can substitute #v=sqrt(x)-1# and then solve the simplified equation to find that #x=16#.

Let's try solving this question using a substitution. We begin by wishing that the pesky #-1# wasn't on the left hand side of the equation, otherwise we'd just square both sides to get rid of the square roots! So let's substitute something that would allow us to do this, let #v=sqrt(x)-1# Then solving for #x# we get #x=(v+1)^2 = v^2+2v+1# We can now substitute the first expression for #v# into the left hand side of the equation, and the second one under the square-root on the right hand side: #sqrt(v^2+2v-6)=v# now we can square both sides: #v^2+2v-6=v^2# We notice the the #v^2#'s on either side cancel out, and then we can solve for #v# giving: #2v-6 = 0 implies v=3# Now we can use our expression for #x# above to solve for #x# #x=(v+1)^2 = 4^2 = 16#

Jameson Allen · Answer

undefined To solve the equation sqrt(x-7) = sqrt(x) - 1, we can follow these steps:

1. Square both sides of the equation to eliminate the square roots:
   (sqrt(x-7))^2 = (sqrt(x) - 1)^2

2. Simplify the equation:
   x - 7 = (sqrt(x))^2 - 2(sqrt(x)) + 1

3. Simplify further:
   x - 7 = x - 2(sqrt(x)) + 1

4. Rearrange the equation:
   x - x - 7 - 1 = -2(sqrt(x))

5. Simplify:
   -8 = -2(sqrt(x))

6. Divide both sides by -2:
   4 = sqrt(x)

7. Square both sides again to eliminate the square root:
   (4)^2 = (sqrt(x))^2

8. Simplify:
   16 = x

Therefore, the solution to the equation sqrt(x-7) = sqrt(x) - 1 is x = 16.