How do you solve #sqrt(x+1) = 2#?

Answer 1

x = 3

To 'undo' the square root we have to perform the inverse operation. The inverse to 'square root' is 'square'. Since this is an equation we must square both sides.

#rArr(sqrt(x+1))^2=2^2rArrx+1=4rArrx=4-1=3#

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Answer 2

Ethan Adkins

#x = 3#

When #sqrt(x + 1) = 2# Square both sides #x + 1 = 4# Subtract #1# from both sides #x = 3#

Check when #x = 3# #3 + 1 = 4# and #sqrt 4 = 2# So answer is correct

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Answer 3

Eva Abramson

To solve the equation sqrt(x+1) = 2, you need to isolate the variable x.

First, square both sides of the equation to eliminate the square root: (sqrt(x+1))^2 = 2^2.

This simplifies to x + 1 = 4.

Next, subtract 1 from both sides of the equation to isolate x: x = 4 - 1.

Therefore, the solution to the equation sqrt(x+1) = 2 is x = 3.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.