How do you solve #\sqrt { - 5x - 9} = 11#?

Answer 1

#x=-26#

Given -

#sqrt(-5x-9)=11#

To eliminate the root, square both sides

#(sqrt(-5x-9))^2=11^2#
#-5x-9=121#
Add #9 #to both sides
#-5x-9+9=121+9# #-5xcancel(-9) cancel(+9)=130# Divide both sides by #-5# #(-5x)/(-5)=130/(-5)# #(cancel(-5)x)/cancel(-5)=130/(-5)# #x=-26#
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Answer 2

To solve the equation \sqrt{-5x-9} = 11, we need to isolate the square root term and then square both sides of the equation.

First, we isolate the square root term by squaring both sides of the equation:

(\sqrt{-5x-9})^2 = 11^2

Simplifying, we get:

-5x-9 = 121

Next, we isolate the variable by moving the constant term to the other side:

-5x = 121 + 9

Simplifying further:

-5x = 130

Finally, we solve for x by dividing both sides of the equation by -5:

x = -130/5

Simplifying the fraction:

x = -26

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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