# How do you solve #sqrt(2x + 10 )- 6 = 2#?

Square both sides to get rid of the radical sign:

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To solve the equation sqrt(2x + 10) - 6 = 2, you can follow these steps:

- Add 6 to both sides of the equation: sqrt(2x + 10) = 8.
- Square both sides of the equation to eliminate the square root: (sqrt(2x + 10))^2 = 8^2.
- Simplify the equation: 2x + 10 = 64.
- Subtract 10 from both sides of the equation: 2x = 54.
- Divide both sides of the equation by 2: x = 27.

Therefore, the solution to the equation sqrt(2x + 10) - 6 = 2 is x = 27.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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