How do you solve #sqrt(1-3x)=-7#?

Answer 1

There is no solution to the given equation.

The definition of the square root symbol is such that its value is always non-negative.

Therefore #sqrt("anything") != "negative value"#
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Answer 2

I found: NO real solutions!

You may square both sides to get: #(sqrt(1-3x))^2=(-7)^2# #1-3x=49# #-3x=48# #x=-16# checking it by substituting back into the original equation: #sqrt(1-3(-16))=-7# #sqrt(49)=-7# #7=-7# NOT TRUE!!!
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Answer 3

To solve the equation sqrt(1-3x)=-7, we need to isolate the variable x.

First, square both sides of the equation to eliminate the square root: 1-3x = 49.

Next, isolate the variable x by subtracting 1 from both sides: -3x = 48.

Finally, divide both sides by -3 to solve for x: x = -16.

Therefore, the solution to the equation sqrt(1-3x)=-7 is x = -16.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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