How do you solve #(sinx+1)-2cosx=0#?
Check by calculator: x = 143.30 --> sin x = 0.60 --> 2cos x = 1.60 0.60 - 1.60 = -1. OK x = 269.82 --> sin x = -1 --> 2cos x = 0 -1 - 0 = -1 . OK
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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