How do you solve # s + 9/10 = 1/2#?

Answer 1

See the entire solution process below:

First, multiply each side of the equation by #color(red)(10)# to eliminate the fractions while keeping the equation balanced:
#color(red)(10)(s + 9/10) = color(red)(10) xx 1/2#
#(color(red)(10) xx s) + (color(red)(10) xx 9/10) = cancel(color(red)(10)) 5 xx 1/color(red)(cancel(color(black)(2)))#
#10s + (cancel(color(red)(10)) xx 9/color(red)(cancel(color(black)(10)))) = 5#
#10s + 9 = 5#
Next, subtract #color(red)(9)# from each side of the equation to isolate the #s# term while keeping the equation balanced:
#10s + 9 - color(red)(9) = 5 - color(red)(9)#
#10s + 0 = -4#
#10s = -4#
Now, divide each side of the equation by #color(red)(10)# to solve for #s# while keeping the equation balanced:
#(10s)/color(red)(10) = -4/color(red)(10)#
#(color(red)(cancel(color(black)(10)))s)/cancel(color(red)(10)) = -2/5#
#s = -2/5#
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Answer 2

To solve the equation ( s + \frac{9}{10} = \frac{1}{2} ), you would first subtract (\frac{9}{10}) from both sides to isolate (s), then simplify to find the solution. The steps are as follows:

  1. Subtract (\frac{9}{10}) from both sides: [ s + \frac{9}{10} - \frac{9}{10} = \frac{1}{2} - \frac{9}{10} ]

  2. Simplify both sides: [ s = \frac{1}{2} - \frac{9}{10} ]

  3. Find a common denominator for (\frac{1}{2}) and (\frac{9}{10}), which is 10: [ s = \frac{5}{10} - \frac{9}{10} ]

  4. Subtract the fractions: [ s = \frac{5 - 9}{10} ]

  5. Simplify the numerator: [ s = \frac{-4}{10} ]

  6. Reduce the fraction: [ s = -\frac{2}{5} ]

So, the solution to the equation is ( s = -\frac{2}{5} ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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