How do you solve #s^2+4s6<0#?
Solution:
graph{x^2+4x6 [12.66, 12.65, 6.33, 6.33]}
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To solve the inequality ( s^2 + 4s  6 < 0 ), follow these steps:

Start by rearranging the inequality so that the quadratic expression is on one side and zero is on the other side:
[ s^2 + 4s  6 < 0 ] [ s^2 + 4s  6 = 0 ]

Next, solve the quadratic equation ( s^2 + 4s  6 = 0 ) to find the critical points. You can use the quadratic formula or factorization to solve for ( s ). The solutions are the points where the quadratic equation crosses the xaxis.

Once you have the critical points, which are the solutions to ( s^2 + 4s  6 = 0 ), plot them on a number line. These points divide the number line into intervals.

Test a value from each interval in the original inequality ( s^2 + 4s  6 < 0 ). Determine whether the inequality is true or false for each interval.

The solution to the inequality is the set of values of ( s ) that make the inequality true. This will be the interval(s) where the inequality is satisfied based on your testing in step 4.
By following these steps, you can find the solution to the inequality ( s^2 + 4s  6 < 0 ) and determine the range of values for ( s ) that satisfy the inequality.
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When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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