How do you solve #root3(y-7)=4#?

Answer 1

Eva Abramson

#y=71#

bringing both concepts up to the cube

#(y-7)=4^3#

#4^3=64#

totaling seven

#(y)=64+7#

#(y)=71#

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Answer 2

Abigail Allen

#y=71#

#root(3)(y-7)=4#

or, #(root(3)(y-7))^3=4^3#

or, #y-7=64#

or, #y=64+7=71#

So the value of #y# is #71#.

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Answer 3

Julia Adams

To solve the equation root3(y-7)=4, you can follow these steps:

Start by isolating the square root term. Divide both sides of the equation by root3 to get y-7 alone on one side: y-7 = 4 * root3.
Next, isolate y by adding 7 to both sides of the equation: y = 4 * root3 + 7.

Therefore, the solution to the equation root3(y-7)=4 is y = 4 * root3 + 7.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.