How do you solve #root3(x)+10=16#?
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To solve the equation √3(x) + 10 = 16, we can start by isolating the square root term. Subtracting 10 from both sides gives us √3(x) = 6. Next, we can square both sides of the equation to eliminate the square root. This gives us 3(x) = 36. Simplifying further, we have x = 12. Therefore, the solution to the equation is x = 12.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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