How do you solve #root3(3x)+6=10#?

Answer 1

#x=64/3#

#root3(3x)+6=10#
#root3(3x)=4#
#(root3(3x))^3=4^3#
#3x=64#
#x=64/3#
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Answer 2

#x=64/3#

We may use the original:

#root(3)(3x)+6=10#

and take six off of each side:

#root(3)(3x)=4#
#3x=64#
#x=64/3#
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Answer 3

To solve the equation √3(3x) + 6 = 10, we can follow these steps:

  1. Start by subtracting 6 from both sides of the equation: √3(3x) = 4.
  2. Divide both sides of the equation by √3: 3x = 4/√3.
  3. Rationalize the denominator by multiplying both the numerator and denominator by √3: 3x = (4/√3) * (√3/√3).
  4. Simplify the right side of the equation: 3x = (4√3)/3.
  5. Divide both sides of the equation by 3: x = (4√3)/9.

Therefore, the solution to the equation √3(3x) + 6 = 10 is x = (4√3)/9.

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Answer 4

To solve the equation root3(3x) + 6 = 10:

  1. Subtract 6 from both sides: root3(3x) = 4.
  2. Square both sides to eliminate the square root: (root3(3x))^2 = 4^2.
  3. Simplify: 3x = 16.
  4. Divide both sides by 3: x = 16/3.

So, the solution is x = 16/3.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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