How do you solve #root3(3x)+6=10#?
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We may use the original:
and take six off of each side:
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To solve the equation √3(3x) + 6 = 10, we can follow these steps:
- Start by subtracting 6 from both sides of the equation: √3(3x) = 4.
- Divide both sides of the equation by √3: 3x = 4/√3.
- Rationalize the denominator by multiplying both the numerator and denominator by √3: 3x = (4/√3) * (√3/√3).
- Simplify the right side of the equation: 3x = (4√3)/3.
- Divide both sides of the equation by 3: x = (4√3)/9.
Therefore, the solution to the equation √3(3x) + 6 = 10 is x = (4√3)/9.
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To solve the equation root3(3x) + 6 = 10:
- Subtract 6 from both sides: root3(3x) = 4.
- Square both sides to eliminate the square root: (root3(3x))^2 = 4^2.
- Simplify: 3x = 16.
- Divide both sides by 3: x = 16/3.
So, the solution is x = 16/3.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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