How do you solve #p( - 5- p ) = 6#?
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Using FOIL method :
Factorization (you can also use quadratic formula and completing square):
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To solve the equation ( p(-5 - p) = 6 ), first distribute ( p ) into the parentheses: ( -5p - p^2 = 6 ). Rearrange the terms to form a quadratic equation: ( p^2 + 5p + 6 = 0 ). Factor the quadratic equation: ( (p + 2)(p + 3) = 0 ). Set each factor equal to zero and solve for ( p ): ( p + 2 = 0 ) or ( p + 3 = 0 ). Therefore, ( p = -2 ) or ( p = -3 ).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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