How do you solve #n/(n+1)=3/5#?

Answer 1

Isolate n.

Firstly we can multiply both sides by #n+1#, doing this, we get: #n/(n+1) * n+1 = 3/5 * (n+1) = n# Now we can multiply both sides by #5#, #n*5 = 3/5*(n+1)*5 -> 5n = 3n + 3#, solving for #n# we get #2n = 3, n = 3/2#

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Answer 2

Julia Adams

n = #3/2#

Cross multiplying must first be understood. For example, 5 would cross with n to make 5n, and 3 would cross with n + 1 to make 3n + 3.

The equation would look like 5n = #3n+3# Bring 3n over to 5n and subtract from both sides. 3n - 3n would cancel out while 5n - 3n would give 2n.

The equation would look like: 2n = 3 Divide 3#divide#2. (Do not be afraid of fractions)

#n=3/2#

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Answer 3

Hazel Anglin

To solve the equation ( \frac{n}{n+1} = \frac{3}{5} ), cross multiply, then solve for ( n ). ( 5n = 3(n + 1) ), ( 5n = 3n + 3 ), ( 2n = 3 ), ( n = \frac{3}{2} )

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.