How do you solve #n^2-9n=-18#?

Answer 1

#n=-3# or #n=6#

Move -18 to the other side of the 'equals to' sign #n^2 -9n+18 = 0#
Find two numbers which when added/subtracted will give the coefficient of n and when multiplied will give the constant number (which has no variables beside it ) #n^2-6n-3n+18=0#
Then factorise common variables/constants #n(n-6)+3(n-6)=0# #(n+3)(n-6)=0#
There are two possible answers #(n+3)=0# or #(n-6)=0# So #n=-3# or #n=6#
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Answer 2

To solve the equation (n^2 - 9n = -18), follow these steps:

  1. Move all terms to one side to set the equation to zero: (n^2 - 9n + 18 = 0).
  2. Factor the quadratic equation: ((n - 6)(n - 3) = 0).
  3. Set each factor equal to zero and solve for (n): [ \begin{align*} n - 6 &= 0 \implies n = 6 \ n - 3 &= 0 \implies n = 3 \end{align*} ]
  4. Therefore, the solutions to the equation are (n = 6) and (n = 3).
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Answer 3

The solution to the equation (n^2 - 9n = -18) is (n = 3) or (n = 6).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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