How do you solve #n-10=5/6n-7-1/3n#?

Answer 1

#n = 6#

Step 1) Get all of the terms containing #n# over a common denominator by multiplying the term by the necessary for of #1#. Step 2) Solve for #n# while keeping the equation balanced
#(6/6)n - 10 = (5/6)n - 7 - (2/2)(1/3)n#
#(6n)/6 -10 = (5n)/6 - 7 - (2n)/6#
#(6n)/6 - 10 = (3n)/6 - 7#
#(6n)/6 - 10 + 10 - (3n)/6 = (3n)/6 - 7 + 10 - (3n)/6#
#(6n)/6 - (3n)/6 = 3#
#(3n)/6 = 3#
#(6/3)((3n)/6) = (6/3)3#
#n = 6#
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Answer 2

To solve the equation (n - 10 = \frac{5}{6}n - 7 - \frac{1}{3}n):

  1. Combine like terms on the right side of the equation.
  2. Move all the terms involving (n) to one side of the equation and the constants to the other side.
  3. Combine like terms again.
  4. Solve for (n).

The solution is (n = \frac{120}{11}).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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