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How do you solve #m+4(2m-3)=-3#?

Answer 1

Nathan Axel

See full solution process below:

We shall first define the terms in parenthesis:

#m + color(red)(4)(2m - 3) = -3#

#m + (color(red)(4) xx 2m) - (color(red)(4) xx 3) = -3#

#m + 8m - 12 = -3#

Now, we can mix similar terms:

#1m + 8m - 12 = -3#

#(1 + 8)m - 12 = -3#

#9m - 12 = -3#

Next we can isolate the #m# term and keep the equation balanced by adding #color(red)(12)# to each side of the equation:

#9m - 12 + color(red)(12) = -3 + color(red)(12)#

#9m - 0 = 9#

#9m = 9#

Now we can solve for #m# while keeping the equation balanced by dividing each side of the equation by #color(red)(9)#:

#(9m)/color(red)(9) = 9/color(red)(9)#

#(color(red)(cancel(color(black)(9)))m)/cancel(color(red)(9)) = 1#

#m = 1#

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Answer 2

Savannah Anderson

To solve for ( m ):

Distribute the 4 across the parentheses.
Combine like terms.
Move all terms containing ( m ) to one side of the equation and constants to the other side.
Solve for ( m ) by isolating it.
Simplify to find the value of ( m ).

Following these steps:

[ m + 4(2m - 3) = -3 ] [ m + 8m - 12 = -3 ] [ 9m - 12 = -3 ] [ 9m = 9 ] [ m = 1 ]

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.