How do you solve #m/2-7>4#?

Answer 1

#m>22#

#m/2-7>4#

Add 7 to both sides.

#m/2>4+7#

Simplify.

#m/2>11#

Multiply both sides by 2.

#m>11xx2#

Simplify.

#m>22#
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Answer 2

#m>22#

Given:#" "m/2-7>4#

You treat this like a normal equation. There is one 'trap' however. If the whole thing is multiplied by a negative number the inequality is turned round the other way.

For example: It is true that #2<4#

Now consider the incorrect calculation of:

#(-1)xx2<(-1)xx4 " implying that " -2<-4# which is false
#-2# is to the right of #-4# on the number line so #-2 > -4#

'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ Add 7 to both sides giving

#m/2-7+7 >4+7#
#m/2+0>11#

Multiply both sides by 2 giving

#2/2xxm>2xx11#
But #2/2 =1# giving:
#m>22#

'~~~~~~~~~~~~~~~~~~~~~~~~~

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Answer 3

To solve the inequality ( \frac{m}{2} - 7 > 4 ), you would first add 7 to both sides to isolate the term with ( m ). This gives you ( \frac{m}{2} > 11 ). Then, to get rid of the fraction, you would multiply both sides by 2, resulting in ( m > 22 ). Therefore, the solution to the inequality is ( m > 22 ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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