# How do you solve # log (x+7)=1#?

I tried this:

using the definition of log we can write:

and:

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To solve the equation log(x + 7) = 1, you can use the definition of logarithms. Rewrite the equation in exponential form: 10^1 = x + 7. Solve for x: 10 = x + 7. Subtract 7 from both sides: x = 10 - 7 = 3. So, the solution to the equation log(x + 7) = 1 is x = 3.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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