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How do you solve # log (x+7)=1#?

Answer 1

Serenity Jones

I tried this:

It depends upon the 'base" of your log. Let us say that is #10#; we can write:

#log_(10)(x+7)=1#

using the definition of log we can write:

#x+7=10^1#

and:

#x=10-7=3#

if you have a different base use the one you got instead of #10#.

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Answer 2

Caleb Alexander

To solve the equation log(x + 7) = 1, you can use the definition of logarithms. Rewrite the equation in exponential form: 10^1 = x + 7. Solve for x: 10 = x + 7. Subtract 7 from both sides: x = 10 - 7 = 3. So, the solution to the equation log(x + 7) = 1 is x = 3.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.