How do you solve #log x=-2#?

Answer 1

Since there is no base noted in subscript to the right of the log, this logarithm is in base 10. We can convert directly to exponential form.

#logx = -2#

#x = 10^-2#

#x = 1/(10^2)#

#x = 1/100#

The answer is #x = 1/100#

Practice exercises:

a) #log(x + 1) = 1#

b) #log_7(x - 2) = 2#

Good luck!

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Answer 2

Sadie Alexander

To solve ( \log(x) = -2 ), you would rewrite it in exponential form as ( x = 10^{-2} ), which simplifies to ( x = 0.01 ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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