How do you solve #log_25 n=3/2#?

Answer 1
We know that if #log_a n = m#, then #n = a^m#.
#n = 25^(3/2)#
#n = (sqrt(25))^3#
#n = (5)^3#
#n = 125#

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Answer 2

To solve the equation log base 5 of n equals 3/2, you can rewrite it in exponential form. Raise the base (5) to the power of the logarithm's value (3/2) to find the value of n. So, n equals 5 raised to the power of 3/2, which simplifies to the square root of 5 cubed. Therefore, n equals the square root of 125, or n = √125.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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