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How do you solve #k/3+k/6=7/2#?

Answer 1

Hazel Anglin

Multiply each term by the common denominator
Solve it!
Find that #k = 7#

As written in the answer, we have to multiply each term by the common denomnator, which is #6#. This gives us:

#(k * 6) / 3 + (k * 6) / 6 = (7 * 6) / 2#

Split up...

#k * 2 + k = 7 * 3#

Fix...

#2k + k = 21# #3k = 21# #k = 7#

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Answer 2

Hazel Anglin

To solve the equation k/3 + k/6 = 7/2, first find a common denominator for the fractions. In this case, the common denominator is 6. Multiply each term by 6 to clear the fractions. The equation becomes 2k + k = 21. Combine like terms: 3k = 21. Divide both sides by 3: k = 7. So, the solution to the equation is k = 7.

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Answer 3

Jace Anderson

To solve the equation ( \frac{k}{3} + \frac{k}{6} = \frac{7}{2} ), follow these steps:

Find a common denominator for the fractions, which is 6.
Rewrite the equation with the common denominator.
Combine like terms.
Solve for ( k ).

[ \frac{2k}{6} + \frac{k}{6} = \frac{7}{2} ]

[ \frac{2k + k}{6} = \frac{7}{2} ]

[ \frac{3k}{6} = \frac{7}{2} ]

[ \frac{k}{2} = \frac{7}{2} ]

[ k = 7 ]

So, the solution for ( k ) is ( k = 7 ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.