How do you solve graphically #abs(x – 4)>abs(3x – 1)#?

Answer 1

#-3/2 < x < 5/4#

The first thing you do is to draw the graphs #y=abs(x-4)# and #y=abs(3x-1)# on the SAME graph

graph{(y-abs(x-4))(y-abs(3x-1))=0 [-20.28, 20.27, -10.14, 10.13]}

Now the question is what parts of the graph above satisfies the equation #abs(x-4) > abs (3x-1)#. What it is asking you is what part of the graph #y=abs(x-4)# is above the graph #y=abs(3x-1)#.
Hence, going from the right, the equation of each branch is #y=x-4#, #y=3x-1#, #y=4-x# and #y=1-3x#.
The branches #y=4-x# and #y=3x-1# meet at a point and so do #y=4-x# and #y=1-3x#

Therefore, we need to find the point of intersection

#y=4-x# and #y=3x-1# #4-x=3x-1# #5=4x# #x=5/4#
#y=4-x# and #y=1-3x# #4-x=1-3x# #2x=-3# #x=-3/2#
Finally, looking at where #y=abs(x-4)# is above the graph #y=abs(3x-1)#, we can tell that it is #-3/2 < x < 5/4#
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Answer 2

To solve graphically the inequality abs(x – 4) > abs(3x – 1), you would plot the graphs of the two expressions abs(x – 4) and abs(3x – 1) on the same coordinate plane. Then, identify the regions where the graph of abs(x – 4) is greater than the graph of abs(3x – 1). These regions represent the solutions to the inequality.

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Answer 3

To solve the inequality ( |x - 4| > |3x - 1| ) graphically, follow these steps:

  1. Graph the functions ( y = |x - 4| ) and ( y = |3x - 1| ) on the same coordinate system.
  2. Identify the regions where one function's value is greater than the other function's value.
  3. The solution to the inequality lies in the regions where ( |x - 4| ) is greater than ( |3x - 1| ).

Here's a step-by-step process:

  1. Graph ( y = |x - 4| ):

    • This function represents the absolute value of ( x - 4 ), which is symmetric around the point ( x = 4 ). It is a V-shaped graph with the vertex at ( (4, 0) ).
  2. Graph ( y = |3x - 1| ):

    • This function represents the absolute value of ( 3x - 1 ), which is symmetric around the point ( x = \frac{1}{3} ). It is also a V-shaped graph, but steeper than the first one, with the vertex at ( \left(\frac{1}{3}, 0\right)).
  3. Identify the regions where ( |x - 4| ) is greater than ( |3x - 1| ):

    • Look for the regions where the graph of ( |x - 4| ) is above the graph of ( |3x - 1| ). This typically involves identifying the areas to the left and right of the intersection point(s) of the two graphs.
  4. Determine the solution:

    • The solution to the inequality is the set of ( x ) values corresponding to the identified regions.

Remember that in a graphical solution, you're looking for the regions where the graph of the left side of the inequality is higher (or lower, depending on the inequality) than the graph of the right side.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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