How do you solve #GaF_3 + Cs -> CsF + Ga#?
The balanced equation for the given reaction is:
[ 2GaF_3 + 6Cs \rightarrow 6CsF + 2Ga ]
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Alkali metals are EXCELLENT reducing agents. We could solve by means of the general method for balancing redox equations, but we could also write the ONE ELECTRON oxidation with respect to the alkali metal directly:
Is this balanced? That is for every reactant particle is there a corresponding product particle? If there are not, then the reaction cannot be accepted as a representation of physical reality.
Note that most of the time, should you use caesium, it is a liquidus, i.e. it has an exceptionally low melting point. It is also mighty expensive.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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