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How do you solve #\frac { y - 6} { y + 8} = \frac { 3} { 5}#?

Answer 1

Avery Alexander

#y=27#

#(y-6)/(y+8)=3/5#

Multiply both sides by #5(y+8)#.

#5(y+8)xx(y-6)/(y+8)=3/5xx5(y+8)#

#5(cancel(y+8))xx(y-6)/(1cancel(y+8))=3/(1cancel5)xx1cancel5(y+8)#

#5xx(y-6)=3xx(y+8)#

Open the brackets and simplify.

#5y-30=3y+24#

Subtract #3y# from each side.

#5y-3y-30=3y-3y+24#

Add #30# to each side.

#2y=24+30#

#2y=54#

Divide both sides by #2#.

#y=54/2#

#y=27#

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Answer 2

Hazel Anglin

To solve the equation (\frac{y - 6}{y + 8} = \frac{3}{5}), cross multiply to get rid of the fractions, then simplify and solve for (y):

[ 5(y - 6) = 3(y + 8) ]

Expanding and simplifying:

[ 5y - 30 = 3y + 24 ]

Rearranging terms:

[ 5y - 3y = 24 + 30 ]

[ 2y = 54 ]

Dividing both sides by 2:

[ y = 27 ]

So, the solution to the equation is (y = 27).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.