How do you solve #\frac { y - 1} { 3} = \frac { y + 1} { 6}#?

Answer 1

#y=3#

#(y-1)/3=(y+1)/6#

To proceed, the fractions have to be changed to share the same common denominator.

Multiply each side by their lowest common multiple, #3*6=18#
#18# x#(y-1)/3=(y+1)/6#x#18#
#(6(y-1))/1=(3(y+1))/1#

Now they share the same denominator of 1.

#6y-6=3y+3#
#6y-3y=3+6#
#3y=9#
#y=9/3 =3#
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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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