How do you solve #\frac { v - 6} { v - 4} = \frac { v } { v + 1}#?
Simplifying further,
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To solve the equation (\frac{v - 6}{v - 4} = \frac{v}{v + 1}), cross multiply to eliminate the fractions. Then, solve for (v).
[ (v - 6)(v + 1) = v(v - 4) ]
[ (v^2 - 5v - 6) = v^2 - 4v ]
[ -v - 6 = -4v ]
[ 6 = 3v ]
[ v = 2 ]
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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