How do you solve #\frac { p + 2} { 7} = - 2#?

Answer 1

#p = 12#

#(p+2)/7 = -2#
To solve for the variable #p#, we have to make it by itself. First, multiply both sides by #color(blue)7#: #(p+2)/7 color(blue)(*7) = -2 color(blue)(*7)#
#p+2 = -14#
Now subtract both sides by #color(blue)2#: #p + 2 quadcolor(blue)(-quad2) = 14 quadcolor(blue)(-quad2)#
Therefore, #p = 12#

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Answer 2

To solve the equation (\frac { p + 2} { 7} = - 2), you would first multiply both sides of the equation by (7) to eliminate the fraction. This gives you (p + 2 = -14). Then, you would subtract (2) from both sides to isolate (p). So, (p = -14 - 2) simplifies to (p = -16). Therefore, the solution to the equation is (p = -16).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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