How do you solve #\frac { 6} { x } = \frac { 4} { 3x } + 1#?
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To solve the equation ( \frac{6}{x} = \frac{4}{3x} + 1 ), follow these steps:

Multiply both sides of the equation by ( 3x ) to eliminate the denominators: [ 3x \times \frac{6}{x} = 3x \times \left(\frac{4}{3x} + 1\right) ]

Simplify: [ 18 = 4 + 3x ]

Subtract 4 from both sides: [ 18  4 = 3x ]

Simplify: [ 14 = 3x ]

Divide both sides by 3 to solve for ( x ): [ x = \frac{14}{3} ]
So, the solution to the equation is ( x = \frac{14}{3} ).
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When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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