Home > Algebra > Two-Step Equations and Properties of Equality

How do you solve #\frac { 6} { 3} x - 4= 2x + 1#?

Answer 1

no solutions or #cancel(0)#

#6/3x - 4 = 2x + 1#

First, add #color(blue)4# to both sides of the equation: #6/3x - 4 quadcolor(blue)(+quad4) = 2x + 1 quadcolor(blue)(+quad4)#

#6/3x = 2x + 5#

We also know that #6/3 = 2#.

#2x = 2x + 5#

Subtract #color(blue)(2x)# from both sides of the equation: #2x quadcolor(blue)(-quad2x) = 2x + 5 quadcolor(blue)(-quad2x)#

#0 = 5#

Oh no! Now we don't have any more variables. We have to now see if this equation is true. #0# does NOT equal to #5#, so the answer is no solutions or #cancel(0)#.

Hope this helps!

By signing up, you agree to our Terms of Service and Privacy Policy

Answer 2

Abigail Allen

To solve the equation (\frac{6}{3}x - 4 = 2x + 1), follow these steps:

Multiply (\frac{6}{3}) to get (2x - 4 = 2x + 1).
Move variables to one side and constants to the other side to isolate (x).
Subtract (2x) from both sides to get (-4 = 1).
Since (-4) is not equal to (1), there is no solution to this equation.

By signing up, you agree to our Terms of Service and Privacy Policy

Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.