How do you solve #\frac { 5x - 3} { 4} = 7#?

Answer 1

Eva Adamson

#x=31/5#

#(5x-3)/4=7#

Multiply by cross

#5x - 3= 7 xx 4#

#5x - 3= 28#

Then add #33# on both sides

#5x - 3 + 3 = 28 + 3#

#5x = 31#

#x = 31/5#

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Answer 2

Savannah Anderson

#x=31/5#

#"to eliminate the fraction multiply both sides by 4"#

#cancel(4)^1xx(5x-3)/cancel(4)^1=4xx7#

#rArr5x-3=28#

#"add 3 to both sides"#

#5xcancel(-3)cancel(+3)=28+3#

#rArr5x=31#

#"divide both sides by 5"#

#(cancel(5) x)/cancel(5)=31/5#

#rArrx=31/5#

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Answer 3

Isaiah Anthony

#x=31/5#

To get rid of the #4# in the denominator, we can multiply both sides by #4# to get

#5x-3=28#

Next, add #3# to both sides to get

#5x=31#

Lastly, we can divide both sides by #5# to get

#x=31/5#

I hope this is useful.

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Answer 4

Avery Alexander

To solve the equation ( \frac{5x - 3}{4} = 7 ), you first multiply both sides by 4 to eliminate the fraction. This gives you ( 5x - 3 = 28 ). Then, you add 3 to both sides to isolate the variable, resulting in ( 5x = 31 ). Finally, you divide both sides by 5 to solve for x, yielding ( x = \frac{31}{5} ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.