How do you solve #\frac { 5} { x + 2} - \frac { 3} { x } = 0#?

Answer 1

#x=3#

#frac{5}{x+2}-3/x=0#

Rewrite the second sentence to include a negative.

#frac{5}{x+2}+(-3)/x=0#
Multiply through by the common denominator #color(red)(x(x+2))#
#color(red)(x(x+2))xxfrac{5}{x+2} + color(red)(x(x+2)) xx frac{-3}{x} = color(red)(x(x+2)) xx 0#
#x(cancel(x+2)) xx 5/cancel(x+2) + cancel(x)(x+2) xx (-3)/cancel(x) =0#
#5x + -3(x+2) =0color(white)(aaa)#Distribute the -3
#5x-3x-6=0 color(white)(aaa)#Combine like terms
#2x-6=0#
#color(white)(aa) +6color(white)(a)+6color(white)(aaa)#Add 6 to both sides
#(2x)/2=6/2color(white)(aaa)#Divide by 2
#x=3#

It's usually a good idea to double-check your answers for extraneous solutions (those that divide by zero or don't work) when solving rational equations.

#5/(3+2) -3/3 = 0#
#color(white)(aaaaa)0=0#
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Answer 2

To solve the equation (\frac{5}{x + 2} - \frac{3}{x} = 0), first, find a common denominator for the fractions, then combine them into a single fraction. Then, solve for (x) by cross-multiplying and simplifying the resulting equation. Finally, solve for (x) to find the value(s) that satisfy the equation.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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