How do you solve #\frac { 4} { 5} x + \frac { 7} { 2} = \frac { 3} { 10}#?

Question

Eva Adamson · Accepted Answer

See below

# 4/5 x + 7/2 = 3/10# First take LCM on both the sides #-> (8x + 35 = 3)/10 # Now you can eliminate the LCM #-> 8x + 35 = 3# #-> 8x = 3 - 35# #-> 8x = -32# Divide both sides by 8 #-> cancel8^1*x/(cancel8) = cancel(-32)^-4/(cancel8)# #-> x = -4#

Ethan Adkins · Answer

take LCM and solve

taking LCM in #4/5x + 7/2 = 3/10# #=> 8/10x + 35/10 = 3/10# #=> 8x + 35 = 3# #=> 8x =-32# #=> x=-4# hope u find it helpful :)

Savannah Anderson · Answer

undefined To solve the equation $\frac{4}{5}x + \frac{7}{2} = \frac{3}{10}$, you first need to isolate the variable $x$. Here's how:

1. Subtract $\frac{7}{2}$ from both sides of the equation:
   $$\frac{4}{5}x = \frac{3}{10} - \frac{7}{2}$$

2. Convert the fractions to have a common denominator, which is 10:
   $$\frac{4}{5}x = \frac{3}{10} - \frac{35}{10}$$

3. Perform the subtraction:
   $$\frac{4}{5}x = \frac{3 - 35}{10}$$
   $$\frac{4}{5}x = \frac{-32}{10}$$

4. Simplify the fraction:
   $$\frac{4}{5}x = -\frac{16}{5}$$

5. Multiply both sides by the reciprocal of $\frac{4}{5}$ to isolate $x$:
   $$x = -\frac{16}{5} \times \frac{5}{4}$$
   $$x = -4$$

So, the solution to the equation is $x = -4$.