# How do you solve #\frac { 2} { 5} = \frac { k + 3} { 15}#?

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To solve the equation (\frac{2}{5} = \frac{k + 3}{15}) for (k), you can cross multiply and then solve for (k).

First, multiply 2 by 15 and 5 by (k + 3):

[2 \times 15 = 5 \times (k + 3)]

Simplify both sides:

[30 = 5(k + 3)]

Now, distribute 5 on the right side:

[30 = 5k + 15]

Subtract 15 from both sides to isolate (5k):

[30 - 15 = 5k] [15 = 5k]

Divide both sides by 5 to solve for (k):

[\frac{15}{5} = \frac{5k}{5}] [3 = k]

So, the solution to the equation is (k = 3).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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