# How do you solve #(\frac { 1} { 81} ) ^ { 6x + 2} = 9^ { 2x ^ { 2} + 12}#?

Work on the left side first:

Our equation now appears as follows:

putting everything aside and gathering in the manner described by our terms:

Splitting the whole by two:

factoring

Solving:

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To solve the equation ((\frac { 1} { 81} ) ^ { 6x + 2} = 9^ { 2x ^ { 2} + 12}), take the logarithm of both sides with the same base, preferably the natural logarithm. Then solve for (x).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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