# How do you solve #\frac { 1} { 7} r + \frac { 53} { 56} > \frac { 6} { 7}#?

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To solve the inequality (\frac{1}{7}r + \frac{53}{56} > \frac{6}{7}), first, subtract (\frac{53}{56}) from both sides to isolate the term with (r). This gives (\frac{1}{7}r > \frac{6}{7} - \frac{53}{56}). Next, find a common denominator for (\frac{6}{7}) and (\frac{53}{56}), which is 56. So, (\frac{6}{7} = \frac{48}{56}). Now, (\frac{6}{7} - \frac{53}{56} = \frac{48}{56} - \frac{53}{56} = \frac{-5}{56}). Therefore, the inequality becomes (\frac{1}{7}r > \frac{-5}{56}). To isolate (r), multiply both sides by (7) to get (r > \frac{-5}{56} \times 7). So, (r > -\frac{5}{8}). Thus, the solution is (r > -\frac{5}{8}).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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