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How do you solve for z in #a = x+y+z/3#?

Answer 1

Abigail Allen

The answer is #z=3(a-x-y)#.

Beginning Equation:

#a=x+y+z/3#

First multiply both sides of the equation by 3.

#3a=3x+3y+z#

Subract 3x and 3y from both sides.

#3a-3x-3y=z#

Factor out the 3.

#3(a-x-y)=z#

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Answer 2

Jace Anderson

To solve for ( z ), you can rearrange the equation to isolate ( z ): [ a = \frac{x + y + z}{3} ] [ 3a = x + y + z ] [ z = 3a - x - y ]

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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