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How do you solve for y in # -x + 2y = 6#?

Answer 1

Avery Alexander

See a solution process below:

First, add #color(red)(x)# to each side of the equation to isolate the #y# term while keeping the equation balanced:

#color(red)(x) - x + 2y = color(red)(x) + 6#

#0 + 2y = x + 6#

#2y = x + 6#

Now, divide each side of the equation by #color(red)(2)# to solve for #y# while keeping the equation balanced:

#(2y)/color(red)(2) = (x + 6)/color(red)(2)#

#(color(red)(cancel(color(black)(2)))y)/cancel(color(red)(2)) = x/color(red)(2) + 6/color(red)(2)#

#y = 1/2x + 3#

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Answer 2

Nathan Axel

To solve for ( y ) in the equation ( -x + 2y = 6 ), you first isolate ( y ) by moving the term containing ( x ) to the other side of the equation.

( -x + 2y = 6 )

Add ( x ) to both sides:

( 2y = x + 6 )

Then, divide both sides by ( 2 ):

( y = \frac{x + 6}{2} )

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.